What is the slant height x of the square pyramid? Express your answer in radical form.
Accepted Solution
A:
Answer:x = [tex] 4 \sqrt { 3 } [/tex]Step-by-step explanation:We are given a diagram of a pyramid with a right angled triangle which has [tex]30[/tex]°, [tex]60[/tex]° and [tex]90[/tex]° angles an the hypotenuse is [tex]8cm[/tex].Since we have a right angled triangle, we can apply sin here:We know that [tex]sin 60 = \frac{\sqrt{3} }{2}[/tex] so we can write it as[tex]\frac{\sqrt{3} }{2} = \frac{x}{8}[/tex]So we get the slant height of x = [tex]4\sqrt{3}[/tex].